Better and better corrections
For 1 − 1/3 + 1/5 − … (a quarter of π) the Kerala texts give three corrections after n terms, each better than the last: 1/(4n), n/(4n² + 1) and (n² + 1)/(4n³ + 5n). This lesson uses the second.
38 / ANTIQUITY TO THE RENAISSANCE
How long is the rim of a well 1 m across? Madhava’s rule builds the answer from pieces of 4, 4/3, 4/5, 4/7, … metres, added and taken back in turn.
Explore the mathematics ↓
01 / AN ENDLESS SUM
Lay pieces of 4, 4/3, 4/5, … metres back and forth along a measuring line, and watch where the rope’s end settles.
A fixed ×5 close-up shows the end swinging past the rim and back, a little less each time.
Stop anywhere and add Madhava’s correction. After only four pieces the end lands within a fifth of a millimetre of the rim.
THE IDEAThe rim of a circle 1 unit across is 4 − 4/3 + 4/5 − 4/7 + … units long: π. The endless sum settles slowly, but the rim always lies inside its last swing, and Madhava’s correction after the odd number p, 4 × ((p + 1) ÷ 2) ÷ ((p + 1)² + 1), lands almost exactly on it.
For 1 − 1/3 + 1/5 − … (a quarter of π) the Kerala texts give three corrections after n terms, each better than the last: 1/(4n), n/(4n² + 1) and (n² + 1)/(4n³ + 5n). This lesson uses the second.
Madhava is also credited with infinite series for the sine, the cosine and the inverse tangent, centuries before they appeared in Europe.