Piles of piles
Zhu went further: 1 + 4 + 10 + 20 + … adds up the pile totals themselves, and he gave its rule too, n(n + 1)(n + 2)(n + 3) ÷ 24.
35 / ANTIQUITY TO THE RENAISSANCE
Stack oranges in triangular layers and count each pile. Subtract neighbouring totals, then subtract again: the changes settle to one steady number.
Explore the mathematics ↓
01 / PILES AND DIFFERENCES
Build piles of 1 to 5 layers and record each total.
Subtract, and subtract again, until the differences stop changing. Then add back up the table to predict the next pile, and build it to check.
THE IDEAEach difference is a real piece of the pile: a new layer, a new row, a single orange. Because the third difference stays the same, adding back up the table predicts the next total, and Zhu’s rule n(n + 1)(n + 2) ÷ 6 gives any total at once.
Zhu went further: 1 + 4 + 10 + 20 + … adds up the pile totals themselves, and he gave its rule too, n(n + 1)(n + 2)(n + 3) ÷ 24.
Using differences, Zhu found how many soldiers are recruited when each day’s intake is a cube, 27, 64, 125, … . After 15 days: 23,400.